PENERAPAN SOAL

1. Masuk lah iNetwork simulator dan buat-lah skema seperti diatas
2. Buat-lah soal yang diberikan guru dan masukkan ke config routing

IIIIIIII.IIIIIIII.IIIIIIII.IIIOOOOO

255.255.255.224

subnet=2x=23

=8

host/subn.et=2y-2=25-2 .

= 32-2=30

blok subnet = 256-224=32

0,32,64,128,150,192,224

Computer A =IP=192.100.60.2

Subnet mask=255.2555.255.2524

Gateway=192.100.60.1

Computer B =IP=192.100.60.34

Subnet mask= 255.255.255.224

Gateway= 192.100.60.33

Computer C =IP=192.100.60.66

Subnet mask=255.255.255.224

Gateway = 192.100.60.65

Computer D = IP=192.100.60.130

Subnet mask= 255.255.255.224

gateway=192.100.60.129

ROUTER 1

Iinterface 1 ip address=192.168.60.1

subnet mask=255.255.255.224

interface2 ip address=192.100.60.33

subnet mask=255.255.255.224

interface 3 ip addres= 192.100.60.193

subnet mask=255.255.255.224

ROUTER 2 interface 1 ip address=192.100.60.65

subnet mask=255.255.255.224

Interface 2 Ip address = 192.100.60.129
Subnet mask=255.255.255.224

Interface 3 Ip address =192.100.60.194
Subnet mask=255.255.255.224

ROUTER 1

Tambah-kan Routing table dgn mengisi sbb:
Destination =192.100.60.64
Subnet mask =255.255.255.224
Next hop =192.100.60.194
Interface =192.100.60.193

tambah satu lagi dgn mengisi sbb:
Destination =192.100.60.128
Subnet mask =255.255.255.224
Next hop =192.100.60.194
Interface =192.100.60.193

ROUTER 2

tambah routing table-nya
Destination =192.100.60.
Subnet mask =255.255.255.224
Next hop =192.100.60.193
Interface =192.100.60.194

tambah lagi
Destination =192.100.60.32
Subnet mask =255.255.255.224
Next hop =192.100.60.193
Interface =192.100.60.194

cek-lah apakah simulator yang kita jadi berhasil/tidak dengan ke command promp